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1004144355551 = 5147195093133
BaseRepresentation
bin11101001110010111010…
…10101110100011011111
310112222212112202111112002
432213023222232203133
5112422441423334201
62045144134232515
7132355430123201
oct16471352564337
93488775674462
101004144355551
11357945346627
12142739ab573b
13738c8a90c2c
143685aa16771
151b1c050376b
hexe9cbaae8df

1004144355551 has 4 divisors (see below), whose sum is σ = 1004339453832. Its totient is φ = 1003949257272.

The previous prime is 1004144355523. The next prime is 1004144355553. The reversal of 1004144355551 is 1555534414001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1004144355551 - 210 = 1004144354527 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1004144355553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97541420 + ... + 97551713.

It is an arithmetic number, because the mean of its divisors is an integer number (251084863458).

Almost surely, 21004144355551 is an apocalyptic number.

1004144355551 is a deficient number, since it is larger than the sum of its proper divisors (195098281).

1004144355551 is an equidigital number, since it uses as much as digits as its factorization.

1004144355551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 195098280.

The product of its (nonzero) digits is 120000, while the sum is 38.

Adding to 1004144355551 its reverse (1555534414001), we get a palindrome (2559678769552).

The spelling of 1004144355551 in words is "one trillion, four billion, one hundred forty-four million, three hundred fifty-five thousand, five hundred fifty-one".

Divisors: 1 5147 195093133 1004144355551