Base | Representation |
---|---|
bin | 11101001110011000101… |
… | …00100001101111110111 |
3 | 10112222220022101012111211 |
4 | 32213030110201233313 |
5 | 112423002230010033 |
6 | 2045145205142251 |
7 | 132355622221423 |
oct | 16471424415767 |
9 | 3488808335454 |
10 | 1004155313143 |
11 | 357950550194 |
12 | 1427416ba987 |
13 | 738cb129608 |
14 | 3685c269b83 |
15 | 1b1c146a2cd |
hex | e9cc521bf7 |
1004155313143 has 2 divisors, whose sum is σ = 1004155313144. Its totient is φ = 1004155313142.
The previous prime is 1004155313131. The next prime is 1004155313159. The reversal of 1004155313143 is 3413135514001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1004155313143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1004155313243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502077656571 + 502077656572.
It is an arithmetic number, because the mean of its divisors is an integer number (502077656572).
Almost surely, 21004155313143 is an apocalyptic number.
1004155313143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004155313143 is an equidigital number, since it uses as much as digits as its factorization.
1004155313143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 31.
The spelling of 1004155313143 in words is "one trillion, four billion, one hundred fifty-five million, three hundred thirteen thousand, one hundred forty-three".
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