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1004155423471 is a prime number
BaseRepresentation
bin11101001110011000101…
…00111100101011101111
310112222220022120210212001
432213030110330223233
5112423002242022341
62045145211353131
7132355623161164
oct16471424745357
93488808523761
101004155423471
11357950616072
121427417527a7
13738cb1678b5
143685c29806b
151b1c148cd31
hexe9cc53caef

1004155423471 has 2 divisors, whose sum is σ = 1004155423472. Its totient is φ = 1004155423470.

The previous prime is 1004155423391. The next prime is 1004155423483. The reversal of 1004155423471 is 1743245514001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1004155423471 - 219 = 1004154899183 is a prime.

It is a super-3 number, since 3×10041554234713 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 1004155423471.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1004155429471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502077711735 + 502077711736.

It is an arithmetic number, because the mean of its divisors is an integer number (502077711736).

Almost surely, 21004155423471 is an apocalyptic number.

1004155423471 is a deficient number, since it is larger than the sum of its proper divisors (1).

1004155423471 is an equidigital number, since it uses as much as digits as its factorization.

1004155423471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 67200, while the sum is 37.

The spelling of 1004155423471 in words is "one trillion, four billion, one hundred fifty-five million, four hundred twenty-three thousand, four hundred seventy-one".