Base | Representation |
---|---|
bin | 101110110000110010… |
… | …0001001000101000101 |
3 | 100121012112001001111101 |
4 | 1131201210021011011 |
5 | 3121130301042013 |
6 | 114044404540101 |
7 | 10153346240446 |
oct | 1354144110505 |
9 | 317175031441 |
10 | 100421112133 |
11 | 39652110961 |
12 | 175669b1631 |
13 | 9614b33714 |
14 | 4c08d5d2cd |
15 | 292b1bd8dd |
hex | 1761909145 |
100421112133 has 2 divisors, whose sum is σ = 100421112134. Its totient is φ = 100421112132.
The previous prime is 100421112119. The next prime is 100421112161. The reversal of 100421112133 is 331211124001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79263082369 + 21158029764 = 281537^2 + 145458^2 .
It is a cyclic number.
It is not a de Polignac number, because 100421112133 - 221 = 100419014981 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 100421112133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100421112173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50210556066 + 50210556067.
It is an arithmetic number, because the mean of its divisors is an integer number (50210556067).
Almost surely, 2100421112133 is an apocalyptic number.
It is an amenable number.
100421112133 is a deficient number, since it is larger than the sum of its proper divisors (1).
100421112133 is an equidigital number, since it uses as much as digits as its factorization.
100421112133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 100421112133 its reverse (331211124001), we get a palindrome (431632236134).
The spelling of 100421112133 in words is "one hundred billion, four hundred twenty-one million, one hundred twelve thousand, one hundred thirty-three".
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