10042412131 has 2 divisors, whose sum is σ = 10042412132. Its totient is φ = 10042412130.

The previous prime is 10042412129. The next prime is 10042412153. The reversal of 10042412131 is 13121424001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10042412131 - 2¹ = 10042412129 is a prime.

It is a super-3 number, since 3×10042412131³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 10042412129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10042412099 and 10042412108.

It is not a weakly prime, because it can be changed into another prime (10042412101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021206065 + 5021206066.

It is an arithmetic number, because the mean of its divisors is an integer number (5021206066).

Almost surely, 2^10042412131 is an apocalyptic number.

10042412131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10042412131 is an equidigital number, since it uses as much as digits as its factorization.

10042412131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 10042412131 its reverse (13121424001), we get a palindrome (23163836132).

The spelling of 10042412131 in words is "ten billion, forty-two million, four hundred twelve thousand, one hundred thirty-one".