Base | Representation |
---|---|
bin | 11101001110100100010… |
… | …11010001010111001111 |
3 | 10120000011011020011012002 |
4 | 32213102023101113033 |
5 | 112423202402100111 |
6 | 2045203034502515 |
7 | 132361224221354 |
oct | 16472213212717 |
9 | 3500134204162 |
10 | 1004253550031 |
11 | 3579a0a47aa6 |
12 | 14276a594a3b |
13 | 739155a3754 |
14 | 3686b31c62b |
15 | 1b1c9dc263b |
hex | e9d22d15cf |
1004253550031 has 2 divisors, whose sum is σ = 1004253550032. Its totient is φ = 1004253550030.
The previous prime is 1004253550007. The next prime is 1004253550037. The reversal of 1004253550031 is 1300553524001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1004253550031 - 230 = 1003179808207 is a prime.
It is a super-2 number, since 2×10042535500312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1004253549976 and 1004253550003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1004253550037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502126775015 + 502126775016.
It is an arithmetic number, because the mean of its divisors is an integer number (502126775016).
Almost surely, 21004253550031 is an apocalyptic number.
1004253550031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004253550031 is an equidigital number, since it uses as much as digits as its factorization.
1004253550031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9000, while the sum is 29.
The spelling of 1004253550031 in words is "one trillion, four billion, two hundred fifty-three million, five hundred fifty thousand, thirty-one".
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