Base | Representation |
---|---|
bin | 11101001110100100100… |
… | …10000000010010101101 |
3 | 10120000011021112211102122 |
4 | 32213102102000102231 |
5 | 112423203330040432 |
6 | 2045203140402325 |
7 | 132361245222365 |
oct | 16472222002255 |
9 | 3500137484378 |
10 | 1004255315117 |
11 | 3579a1a4314a |
12 | 14276b0a63a5 |
13 | 73915a70c92 |
14 | 3686b65b9a5 |
15 | 1b1ca120612 |
hex | e9d24804ad |
1004255315117 has 2 divisors, whose sum is σ = 1004255315118. Its totient is φ = 1004255315116.
The previous prime is 1004255315113. The next prime is 1004255315137. The reversal of 1004255315117 is 7115135524001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1002523590121 + 1731724996 = 1001261^2 + 41614^2 .
It is a cyclic number.
It is not a de Polignac number, because 1004255315117 - 22 = 1004255315113 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1004255315111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502127657558 + 502127657559.
It is an arithmetic number, because the mean of its divisors is an integer number (502127657559).
Almost surely, 21004255315117 is an apocalyptic number.
It is an amenable number.
1004255315117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004255315117 is an equidigital number, since it uses as much as digits as its factorization.
1004255315117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21000, while the sum is 35.
The spelling of 1004255315117 in words is "one trillion, four billion, two hundred fifty-five million, three hundred fifteen thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.100 sec. • engine limits •