10043104481 has 2 divisors, whose sum is σ = 10043104482. Its totient is φ = 10043104480.

The previous prime is 10043104469. The next prime is 10043104483. The reversal of 10043104481 is 18440134001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8164748881 + 1878355600 = 90359^2 + 43340^2 .

It is an emirp because it is prime and its reverse (18440134001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10043104481 is a prime.

It is a super-2 number, since 2×10043104481² (a number of 21 digits) contains 22 as substring.

Together with 10043104483, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10043104481.

It is not a weakly prime, because it can be changed into another prime (10043104483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021552240 + 5021552241.

It is an arithmetic number, because the mean of its divisors is an integer number (5021552241).

Almost surely, 2^10043104481 is an apocalyptic number.

It is an amenable number.

10043104481 is a deficient number, since it is larger than the sum of its proper divisors (1).

10043104481 is an equidigital number, since it uses as much as digits as its factorization.

10043104481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 10043104481 its reverse (18440134001), we get a palindrome (28483238482).

The spelling of 10043104481 in words is "ten billion, forty-three million, one hundred four thousand, four hundred eighty-one".