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100445131 is a prime number
BaseRepresentation
bin1011111110010…
…10101111001011
321000000010211001
411333022233023
5201203221011
613544515431
72326524643
oct577125713
9230003731
10100445131
1151775a06
122977bb77
1317a6b2b7
14d4a9523
158c417c1
hex5fcabcb

100445131 has 2 divisors, whose sum is σ = 100445132. Its totient is φ = 100445130.

The previous prime is 100445099. The next prime is 100445141. The reversal of 100445131 is 131544001.

It is a strong prime.

It is an emirp because it is prime and its reverse (131544001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100445131 - 25 = 100445099 is a prime.

It is a super-2 number, since 2×1004451312 = 20178448683214322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100445099 and 100445108.

It is not a weakly prime, because it can be changed into another prime (100445141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50222565 + 50222566.

It is an arithmetic number, because the mean of its divisors is an integer number (50222566).

Almost surely, 2100445131 is an apocalyptic number.

100445131 is a deficient number, since it is larger than the sum of its proper divisors (1).

100445131 is an equidigital number, since it uses as much as digits as its factorization.

100445131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 100445131 is about 10022.2318372706. The cubic root of 100445131 is about 464.8465690274.

Adding to 100445131 its reverse (131544001), we get a palindrome (231989132).

It can be divided in two parts, 100445 and 131, that added together give a triangular number (100576 = T448).

The spelling of 100445131 in words is "one hundred million, four hundred forty-five thousand, one hundred thirty-one".