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100474874127373 is a prime number
BaseRepresentation
bin10110110110000110100001…
…001011100110010000001101
3111011202022012201202122221011
4112312012201023212100031
5101132140020234033443
6553405304151205221
730110033021466634
oct2666064113462015
9434668181678834
10100474874127373
112a018178085689
12b328854076811
13440a980958565
141ab501d08451b
15b938ae669b9d
hex5b61a12e640d

100474874127373 has 2 divisors, whose sum is σ = 100474874127374. Its totient is φ = 100474874127372.

The previous prime is 100474874127317. The next prime is 100474874127389. The reversal of 100474874127373 is 373721478474001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64869283897609 + 35605590229764 = 8054147^2 + 5967042^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100474874127373 is a prime.

It is a super-2 number, since 2×1004748741273732 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100474875127373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50237437063686 + 50237437063687.

It is an arithmetic number, because the mean of its divisors is an integer number (50237437063687).

Almost surely, 2100474874127373 is an apocalyptic number.

It is an amenable number.

100474874127373 is a deficient number, since it is larger than the sum of its proper divisors (1).

100474874127373 is an equidigital number, since it uses as much as digits as its factorization.

100474874127373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22127616, while the sum is 58.

The spelling of 100474874127373 in words is "one hundred trillion, four hundred seventy-four billion, eight hundred seventy-four million, one hundred twenty-seven thousand, three hundred seventy-three".