Base | Representation |
---|---|
bin | 10010101110000011… |
… | …10111110100001011 |
3 | 221221101221002102021 |
4 | 21113001313310023 |
5 | 131040302340042 |
6 | 4341131145311 |
7 | 504022646224 |
oct | 112701676413 |
9 | 27841832367 |
10 | 10050043147 |
11 | 4297a95191 |
12 | 1b458a5237 |
13 | c4218c3c1 |
14 | 6b4a6c24b |
15 | 3dc495867 |
hex | 257077d0b |
10050043147 has 2 divisors, whose sum is σ = 10050043148. Its totient is φ = 10050043146.
The previous prime is 10050043121. The next prime is 10050043163. The reversal of 10050043147 is 74134005001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10050043147 - 231 = 7902559499 is a prime.
It is not a weakly prime, because it can be changed into another prime (10050043117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5025021573 + 5025021574.
It is an arithmetic number, because the mean of its divisors is an integer number (5025021574).
Almost surely, 210050043147 is an apocalyptic number.
10050043147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10050043147 is an equidigital number, since it uses as much as digits as its factorization.
10050043147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1680, while the sum is 25.
Adding to 10050043147 its reverse (74134005001), we get a palindrome (84184048148).
The spelling of 10050043147 in words is "ten billion, fifty million, forty-three thousand, one hundred forty-seven".
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