Base | Representation |
---|---|
bin | 11101010000001000110… |
… | …00100111100100001001 |
3 | 10120002022212021110100011 |
4 | 32220010120213210021 |
5 | 112431414023102031 |
6 | 2045422405311521 |
7 | 132421133161315 |
oct | 16500430474411 |
9 | 3502285243304 |
10 | 1005095909641 |
11 | 35829349026a |
12 | 1429647055a1 |
13 | 73a1ac681a5 |
14 | 3690b152b45 |
15 | 1b228d156b1 |
hex | ea04627909 |
1005095909641 has 2 divisors, whose sum is σ = 1005095909642. Its totient is φ = 1005095909640.
The previous prime is 1005095909639. The next prime is 1005095909663. The reversal of 1005095909641 is 1469095905001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 913773487225 + 91322422416 = 955915^2 + 302196^2 .
It is a cyclic number.
It is not a de Polignac number, because 1005095909641 - 21 = 1005095909639 is a prime.
Together with 1005095909639, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1005095909341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502547954820 + 502547954821.
It is an arithmetic number, because the mean of its divisors is an integer number (502547954821).
Almost surely, 21005095909641 is an apocalyptic number.
It is an amenable number.
1005095909641 is a deficient number, since it is larger than the sum of its proper divisors (1).
1005095909641 is an equidigital number, since it uses as much as digits as its factorization.
1005095909641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 437400, while the sum is 49.
The spelling of 1005095909641 in words is "one trillion, five billion, ninety-five million, nine hundred nine thousand, six hundred forty-one".
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