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10051213543 = 72205126807
BaseRepresentation
bin10010101110001100…
…10101100011100111
3221221111010112220021
421113012111203213
5131041102313133
64341212220011
7504035622400
oct112706254347
927844115807
1010051213543
114298714558
121b4616a607
13c424ac047
146b4c949a7
153dc62752d
hex2571958e7

10051213543 has 6 divisors (see below), whose sum is σ = 11692228056. Its totient is φ = 8615325852.

The previous prime is 10051213537. The next prime is 10051213583. The reversal of 10051213543 is 34531215001.

It is a happy number.

It is not a de Polignac number, because 10051213543 - 217 = 10051082471 is a prime.

It is a super-2 number, since 2×100512135432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10051213583) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 102563355 + ... + 102563452.

It is an arithmetic number, because the mean of its divisors is an integer number (1948704676).

Almost surely, 210051213543 is an apocalyptic number.

10051213543 is a deficient number, since it is larger than the sum of its proper divisors (1641014513).

10051213543 is an equidigital number, since it uses as much as digits as its factorization.

10051213543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 205126821 (or 205126814 counting only the distinct ones).

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 10051213543 its reverse (34531215001), we get a palindrome (44582428544).

The spelling of 10051213543 in words is "ten billion, fifty-one million, two hundred thirteen thousand, five hundred forty-three".

Divisors: 1 7 49 205126807 1435887649 10051213543