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100514131253 is a prime number
BaseRepresentation
bin101110110011100011…
…0111110110100110101
3100121110000001220201222
41131213012332310311
53121323104200003
6114101530400125
710155556006304
oct1354706766465
9317400056658
10100514131253
113969a674568
1217591b90045
13962b1a1913
144c1745443b
152934444c38
hex17671bed35

100514131253 has 2 divisors, whose sum is σ = 100514131254. Its totient is φ = 100514131252.

The previous prime is 100514131241. The next prime is 100514131273. The reversal of 100514131253 is 352131415001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71811672529 + 28702458724 = 267977^2 + 169418^2 .

It is a cyclic number.

It is not a de Polignac number, because 100514131253 - 230 = 99440389429 is a prime.

It is a super-2 number, since 2×1005141312532 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100514131273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50257065626 + 50257065627.

It is an arithmetic number, because the mean of its divisors is an integer number (50257065627).

Almost surely, 2100514131253 is an apocalyptic number.

It is an amenable number.

100514131253 is a deficient number, since it is larger than the sum of its proper divisors (1).

100514131253 is an equidigital number, since it uses as much as digits as its factorization.

100514131253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 100514131253 its reverse (352131415001), we get a palindrome (452645546254).

The spelling of 100514131253 in words is "one hundred billion, five hundred fourteen million, one hundred thirty-one thousand, two hundred fifty-three".