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100521131040000 = 283254119765423
BaseRepresentation
bin10110110110110001100110…
…010011101101110100000000
3111011220201121110022021222100
4112312301212103231310000
5101133414234021240000
6553442434201310400
730113261222661336
oct2666614623556400
9434821543267870
10100521131040000
112a0358549897a0
12b335803495400
134412143099788
141ab736a619b56
15b94bba5d6a00
hex5b6c664edd00

100521131040000 has 1080 divisors, whose sum is σ = 399171661080192. Its totient is φ = 24117166080000.

The previous prime is 100521131039993. The next prime is 100521131040007. The reversal of 100521131040000 is 40131125001.

100521131040000 is a `hidden beast` number, since 10 + 0 + 521 + 131 + 0 + 4 + 0 + 0 + 0 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (100521131039993) and next prime (100521131040007).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100521131040007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 1536447289 + ... + 1536512711.

Almost surely, 2100521131040000 is an apocalyptic number.

100521131040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 100521131040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (199585830540096).

100521131040000 is an abundant number, since it is smaller than the sum of its proper divisors (298650530040192).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100521131040000 is an equidigital number, since it uses as much as digits as its factorization.

100521131040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65573 (or 65541 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

Adding to 100521131040000 its reverse (40131125001), we get a palindrome (100561262165001).

The spelling of 100521131040000 in words is "one hundred trillion, five hundred twenty-one billion, one hundred thirty-one million, forty thousand".