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10054434343 is a prime number
BaseRepresentation
bin10010101110100101…
…00111111000100111
3221221201012012000011
421113102213320213
5131042413344333
64341405231051
7504105165442
oct112722477047
927851165004
1010054434343
11429a514378
121b47262487
13c43069045
146b5492659
153dca619cd
hex2574a7e27

10054434343 has 2 divisors, whose sum is σ = 10054434344. Its totient is φ = 10054434342.

The previous prime is 10054434289. The next prime is 10054434361. The reversal of 10054434343 is 34343445001.

10054434343 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (34343445001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10054434343 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10054434743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5027217171 + 5027217172.

It is an arithmetic number, because the mean of its divisors is an integer number (5027217172).

Almost surely, 210054434343 is an apocalyptic number.

10054434343 is a deficient number, since it is larger than the sum of its proper divisors (1).

10054434343 is an equidigital number, since it uses as much as digits as its factorization.

10054434343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 10054434343 its reverse (34343445001), we get a palindrome (44397879344).

The spelling of 10054434343 in words is "ten billion, fifty-four million, four hundred thirty-four thousand, three hundred forty-three".