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100550280253 is a prime number
BaseRepresentation
bin101110110100101000…
…0111000010000111101
3100121112112002110211211
41131221100320100331
53121411332432003
6114105301244421
710156505165053
oct1355120702075
9317475073754
10100550280253
1139709014875
12175a2103711
13963581a667
144c1c1841d3
1529376d596d
hex176943843d

100550280253 has 2 divisors, whose sum is σ = 100550280254. Its totient is φ = 100550280252.

The previous prime is 100550280241. The next prime is 100550280263. The reversal of 100550280253 is 352082055001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82942848004 + 17607432249 = 287998^2 + 132693^2 .

It is a cyclic number.

It is not a de Polignac number, because 100550280253 - 217 = 100550149181 is a prime.

It is a super-2 number, since 2×1005502802532 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100550280263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50275140126 + 50275140127.

It is an arithmetic number, because the mean of its divisors is an integer number (50275140127).

Almost surely, 2100550280253 is an apocalyptic number.

It is an amenable number.

100550280253 is a deficient number, since it is larger than the sum of its proper divisors (1).

100550280253 is an equidigital number, since it uses as much as digits as its factorization.

100550280253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 100550280253 in words is "one hundred billion, five hundred fifty million, two hundred eighty thousand, two hundred fifty-three".