100557043 has 2 divisors, whose sum is σ = 100557044. Its totient is φ = 100557042.

The previous prime is 100557031. The next prime is 100557047. The reversal of 100557043 is 340755001.

It is a strong prime.

It is an emirp because it is prime and its reverse (340755001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100557043 - 2⁵ = 100557011 is a prime.

It is a super-2 number, since 2×100557043² = 20223437793807698, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100556999 and 100557017.

It is not a weakly prime, because it can be changed into another prime (100557047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50278521 + 50278522.

It is an arithmetic number, because the mean of its divisors is an integer number (50278522).

Almost surely, 2^100557043 is an apocalyptic number.

100557043 is a deficient number, since it is larger than the sum of its proper divisors (1).

100557043 is an equidigital number, since it uses as much as digits as its factorization.

100557043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2100, while the sum is 25.

The square root of 100557043 is about 10027.8134705428. The cubic root of 100557043 is about 465.0191428509.

The spelling of 100557043 in words is "one hundred million, five hundred fifty-seven thousand, forty-three".