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100561436117 is a prime number
BaseRepresentation
bin101110110100111101…
…1011011110111010101
3100121120022002020210222
41131221323123313111
53121422211423432
6114110340324125
710160002050332
oct1355173336725
9317508066728
10100561436117
113971434439a
12175a59a3645
139637c2536c
144c1d849989
15293868b112
hex1769edbdd5

100561436117 has 2 divisors, whose sum is σ = 100561436118. Its totient is φ = 100561436116.

The previous prime is 100561436071. The next prime is 100561436159. The reversal of 100561436117 is 711634165001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95066772241 + 5494663876 = 308329^2 + 74126^2 .

It is a cyclic number.

It is not a de Polignac number, because 100561436117 - 28 = 100561435861 is a prime.

It is a super-2 number, since 2×1005614361172 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100561436167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50280718058 + 50280718059.

It is an arithmetic number, because the mean of its divisors is an integer number (50280718059).

Almost surely, 2100561436117 is an apocalyptic number.

It is an amenable number.

100561436117 is a deficient number, since it is larger than the sum of its proper divisors (1).

100561436117 is an equidigital number, since it uses as much as digits as its factorization.

100561436117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 35.

The spelling of 100561436117 in words is "one hundred billion, five hundred sixty-one million, four hundred thirty-six thousand, one hundred seventeen".