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10056400513 is a prime number
BaseRepresentation
bin10010101110110100…
…00111111010000001
3221221211220002002021
421113122013322001
5131043414304023
64341515321441
7504130664635
oct112732077201
927854802067
1010056400513
1142a0637605
121b47a50281
13c435a6c63
146b5844dc5
153dccee35d
hex257687e81

10056400513 has 2 divisors, whose sum is σ = 10056400514. Its totient is φ = 10056400512.

The previous prime is 10056400463. The next prime is 10056400517. The reversal of 10056400513 is 31500465001.

10056400513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10011403249 + 44997264 = 100057^2 + 6708^2 .

It is a cyclic number.

It is not a de Polignac number, because 10056400513 - 233 = 1466465921 is a prime.

It is a super-2 number, since 2×100564005132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10056400517) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5028200256 + 5028200257.

It is an arithmetic number, because the mean of its divisors is an integer number (5028200257).

Almost surely, 210056400513 is an apocalyptic number.

It is an amenable number.

10056400513 is a deficient number, since it is larger than the sum of its proper divisors (1).

10056400513 is an equidigital number, since it uses as much as digits as its factorization.

10056400513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 10056400513 its reverse (31500465001), we get a palindrome (41556865514).

The spelling of 10056400513 in words is "ten billion, fifty-six million, four hundred thousand, five hundred thirteen".