10060551131 has 2 divisors, whose sum is σ = 10060551132. Its totient is φ = 10060551130.

The previous prime is 10060551103. The next prime is 10060551133. The reversal of 10060551131 is 13115506001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10060551131 - 2¹⁴ = 10060534747 is a prime.

It is a super-2 number, since 2×10060551131² (a number of 21 digits) contains 22 as substring.

Together with 10060551133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10060551097 and 10060551106.

It is not a weakly prime, because it can be changed into another prime (10060551133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5030275565 + 5030275566.

It is an arithmetic number, because the mean of its divisors is an integer number (5030275566).

Almost surely, 2^10060551131 is an apocalyptic number.

10060551131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10060551131 is an equidigital number, since it uses as much as digits as its factorization.

10060551131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 450, while the sum is 23.

The spelling of 10060551131 in words is "ten billion, sixty million, five hundred fifty-one thousand, one hundred thirty-one".