Base | Representation |
---|---|
bin | 10010101111011001… |
… | …11001100001000011 |
3 | 221222012011010111221 |
4 | 21113230321201003 |
5 | 131101144303212 |
6 | 4342213015511 |
7 | 504220554121 |
oct | 112754714103 |
9 | 27865133457 |
10 | 10061322307 |
11 | 42a3399403 |
12 | 1b49624597 |
13 | c4460b26a |
14 | 6b6366911 |
15 | 3dd472807 |
hex | 257b39843 |
10061322307 has 2 divisors, whose sum is σ = 10061322308. Its totient is φ = 10061322306.
The previous prime is 10061322269. The next prime is 10061322311. The reversal of 10061322307 is 70322316001.
10061322307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10061322307 is a prime.
It is not a weakly prime, because it can be changed into another prime (10061322367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5030661153 + 5030661154.
It is an arithmetic number, because the mean of its divisors is an integer number (5030661154).
Almost surely, 210061322307 is an apocalyptic number.
10061322307 is a deficient number, since it is larger than the sum of its proper divisors (1).
10061322307 is an equidigital number, since it uses as much as digits as its factorization.
10061322307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 10061322307 its reverse (70322316001), we get a palindrome (80383638308).
The spelling of 10061322307 in words is "ten billion, sixty-one million, three hundred twenty-two thousand, three hundred seven".
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