100614013649 has 2 divisors, whose sum is σ = 100614013650. Its totient is φ = 100614013648.

The previous prime is 100614013639. The next prime is 100614013651. The reversal of 100614013649 is 946310416001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84483235600 + 16130778049 = 290660^2 + 127007^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100614013649 is a prime.

It is a super-2 number, since 2×100614013649² (a number of 23 digits) contains 22 as substring.

Together with 100614013651, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (100614013609) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50307006824 + 50307006825.

It is an arithmetic number, because the mean of its divisors is an integer number (50307006825).

Almost surely, 2^100614013649 is an apocalyptic number.

It is an amenable number.

100614013649 is a deficient number, since it is larger than the sum of its proper divisors (1).

100614013649 is an equidigital number, since it uses as much as digits as its factorization.

100614013649 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 100614013649 in words is "one hundred billion, six hundred fourteen million, thirteen thousand, six hundred forty-nine".