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100812113740813 is a prime number
BaseRepresentation
bin10110111011000000100110…
…001110101000010000001101
3111012221112200112121001200111
4112323000212032220100031
5101203201202104201223
6554224240134400021
730143302105063006
oct2673004616502015
9435845615531614
10100812113740813
112a1381a5049712
12b382090b00011
13443370699c097
141ac7491d221ad
15b9c54b2ed30d
hex5bb0263a840d

100812113740813 has 2 divisors, whose sum is σ = 100812113740814. Its totient is φ = 100812113740812.

The previous prime is 100812113740757. The next prime is 100812113740823. The reversal of 100812113740813 is 318047311218001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80749579849929 + 20062533890884 = 8986077^2 + 4479122^2 .

It is an emirp because it is prime and its reverse (318047311218001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100812113740813 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100812113740823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50406056870406 + 50406056870407.

It is an arithmetic number, because the mean of its divisors is an integer number (50406056870407).

Almost surely, 2100812113740813 is an apocalyptic number.

It is an amenable number.

100812113740813 is a deficient number, since it is larger than the sum of its proper divisors (1).

100812113740813 is an equidigital number, since it uses as much as digits as its factorization.

100812113740813 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32256, while the sum is 40.

Adding to 100812113740813 its reverse (318047311218001), we get a palindrome (418859424958814).

The spelling of 100812113740813 in words is "one hundred trillion, eight hundred twelve billion, one hundred thirteen million, seven hundred forty thousand, eight hundred thirteen".