Base | Representation |
---|---|
bin | 1001001011101011101111… |
… | …1000110101011100001111 |
3 | 1022202012101021102202111101 |
4 | 2102322323320311130033 |
5 | 2310404233244241301 |
6 | 33250104324203531 |
7 | 2061302232530422 |
oct | 222727370653417 |
9 | 38665337382441 |
10 | 10096325383951 |
11 | 3242911517754 |
12 | 117089ab395a7 |
13 | 583105591231 |
14 | 26c9441399b9 |
15 | 12796677c701 |
hex | 92ebbe3570f |
10096325383951 has 2 divisors, whose sum is σ = 10096325383952. Its totient is φ = 10096325383950.
The previous prime is 10096325383939. The next prime is 10096325383973. The reversal of 10096325383951 is 15938352369001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10096325383951 - 25 = 10096325383919 is a prime.
It is a super-2 number, since 2×100963253839512 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10096325383892 and 10096325383901.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10096325381951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5048162691975 + 5048162691976.
It is an arithmetic number, because the mean of its divisors is an integer number (5048162691976).
Almost surely, 210096325383951 is an apocalyptic number.
10096325383951 is a deficient number, since it is larger than the sum of its proper divisors (1).
10096325383951 is an equidigital number, since it uses as much as digits as its factorization.
10096325383951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5248800, while the sum is 55.
The spelling of 10096325383951 in words is "ten trillion, ninety-six billion, three hundred twenty-five million, three hundred eighty-three thousand, nine hundred fifty-one".
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