Search a number
-
+
100992821140927 is a prime number
BaseRepresentation
bin10110111101101000111001…
…001110101001110110111111
3111020120211010100110010110101
4112331220321032221312333
5101214131244203002202
6554443243405221531
730162330153455062
oct2675507116516677
9436524110403411
10100992821140927
112a1a78a6724a91
12b3b11035618a7
134447775044081
141ad2115a608d9
15ba20c5b8b887
hex5bda393a9dbf

100992821140927 has 2 divisors, whose sum is σ = 100992821140928. Its totient is φ = 100992821140926.

The previous prime is 100992821140909. The next prime is 100992821141087. The reversal of 100992821140927 is 729041128299001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100992821140927 - 239 = 100443065327039 is a prime.

It is a super-3 number, since 3×1009928211409273 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100992821140327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50496410570463 + 50496410570464.

It is an arithmetic number, because the mean of its divisors is an integer number (50496410570464).

Almost surely, 2100992821140927 is an apocalyptic number.

100992821140927 is a deficient number, since it is larger than the sum of its proper divisors (1).

100992821140927 is an equidigital number, since it uses as much as digits as its factorization.

100992821140927 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1306368, while the sum is 55.

The spelling of 100992821140927 in words is "one hundred trillion, nine hundred ninety-two billion, eight hundred twenty-one million, one hundred forty thousand, nine hundred twenty-seven".