Base | Representation |
---|---|
bin | 11101011001010001000… |
… | …10011000101001111011 |
3 | 10120112222110022211111211 |
4 | 32230220202120221323 |
5 | 113021433314321313 |
6 | 2051553021503551 |
7 | 132653451252424 |
oct | 16545042305173 |
9 | 3515873284454 |
10 | 1009997417083 |
11 | 35a379236366 |
12 | 1438b2111bb7 |
13 | 7431c590455 |
14 | 36c540d664b |
15 | 1b4142b3e3d |
hex | eb28898a7b |
1009997417083 has 2 divisors, whose sum is σ = 1009997417084. Its totient is φ = 1009997417082.
The previous prime is 1009997417081. The next prime is 1009997417113. The reversal of 1009997417083 is 3807147999001.
1009997417083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1009997417083 - 21 = 1009997417081 is a prime.
Together with 1009997417081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1009997417081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 504998708541 + 504998708542.
It is an arithmetic number, because the mean of its divisors is an integer number (504998708542).
Almost surely, 21009997417083 is an apocalyptic number.
1009997417083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1009997417083 is an equidigital number, since it uses as much as digits as its factorization.
1009997417083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3429216, while the sum is 58.
The spelling of 1009997417083 in words is "one trillion, nine billion, nine hundred ninety-seven million, four hundred seventeen thousand, eighty-three".
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