1010000000083 has 2 divisors, whose sum is σ = 1010000000084. Its totient is φ = 1010000000082.

The previous prime is 1010000000057. The next prime is 1010000000143. The reversal of 1010000000083 is 3800000000101.

1010000000083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1010000000083 is a prime.

It is not a weakly prime, because it can be changed into another prime (1010000000783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505000000041 + 505000000042.

It is an arithmetic number, because the mean of its divisors is an integer number (505000000042).

Almost surely, 2^{1010000000083} is an apocalyptic number.

1010000000083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010000000083 is an equidigital number, since it uses as much as digits as its factorization.

1010000000083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1010000000083 its reverse (3800000000101), we get a palindrome (4810000000184).

The spelling of 1010000000083 in words is "one trillion, ten billion, eighty-three", and thus it is an aban number and an uban number.