Base | Representation |
---|---|
bin | 10110111101101111101011… |
… | …110011000101001110111111 |
3 | 111020121111221110111020121100 |
4 | 112331233223303011032333 |
5 | 101214241212133030413 |
6 | 554450451053504143 |
7 | 30163005633661545 |
oct | 2675575363051677 |
9 | 436544843436540 |
10 | 101000112001983 |
11 | 2a1aa9a8180897 |
12 | b3b25b91a2053 |
13 | 444836769813c |
14 | 1ad2608091d95 |
15 | ba23a0caba73 |
hex | 5bdbebcc53bf |
101000112001983 has 48 divisors (see below), whose sum is σ = 153163483200000. Its totient is φ = 64049380632384.
The previous prime is 101000112001927. The next prime is 101000112001991. The reversal of 101000112001983 is 389100211000101.
It is not a de Polignac number, because 101000112001983 - 28 = 101000112001727 is a prime.
It is a super-2 number, since 2×1010001120019832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101000192001983) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1283518 + ... + 14270516.
It is an arithmetic number, because the mean of its divisors is an integer number (3190905900000).
Almost surely, 2101000112001983 is an apocalyptic number.
101000112001983 is a deficient number, since it is larger than the sum of its proper divisors (52163371198017).
101000112001983 is a wasteful number, since it uses less digits than its factorization.
101000112001983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12987476 (or 12987473 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 27.
The spelling of 101000112001983 in words is "one hundred one trillion, one hundred twelve million, one thousand, nine hundred eighty-three".
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