1010012001133 has 2 divisors, whose sum is σ = 1010012001134. Its totient is φ = 1010012001132.

The previous prime is 1010012001121. The next prime is 1010012001199. The reversal of 1010012001133 is 3311002100101.

1010012001133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 984385434244 + 25626566889 = 992162^2 + 160083^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1010012001133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1010012041133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505006000566 + 505006000567.

It is an arithmetic number, because the mean of its divisors is an integer number (505006000567).

Almost surely, 2^{1010012001133} is an apocalyptic number.

It is an amenable number.

1010012001133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010012001133 is an equidigital number, since it uses as much as digits as its factorization.

1010012001133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1010012001133 its reverse (3311002100101), we get a palindrome (4321014101234).

The spelling of 1010012001133 in words is "one trillion, ten billion, twelve million, one thousand, one hundred thirty-three".