Base | Representation |
---|---|
bin | 10010110100000010… |
… | …00100100111011011 |
3 | 222001220020112210021 |
4 | 21122001010213123 |
5 | 131141120240313 |
6 | 4350121331311 |
7 | 505201662301 |
oct | 113201044733 |
9 | 28056215707 |
10 | 10100165083 |
11 | 4313309578 |
12 | 1b5a636b37 |
13 | c4c68b158 |
14 | 6bb598271 |
15 | 3e1a9678d |
hex | 25a0449db |
10100165083 has 2 divisors, whose sum is σ = 10100165084. Its totient is φ = 10100165082.
The previous prime is 10100165039. The next prime is 10100165113. The reversal of 10100165083 is 38056100101.
It is a strong prime.
It is an emirp because it is prime and its reverse (38056100101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10100165083 - 217 = 10100034011 is a prime.
It is not a weakly prime, because it can be changed into another prime (10100163083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050082541 + 5050082542.
It is an arithmetic number, because the mean of its divisors is an integer number (5050082542).
Almost surely, 210100165083 is an apocalyptic number.
10100165083 is a deficient number, since it is larger than the sum of its proper divisors (1).
10100165083 is an equidigital number, since it uses as much as digits as its factorization.
10100165083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 10100165083 its reverse (38056100101), we get a palindrome (48156265184).
The spelling of 10100165083 in words is "ten billion, one hundred million, one hundred sixty-five thousand, eighty-three".
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