1010021131300 has 72 divisors (see below), whose sum is σ = 2212009422336. Its totient is φ = 400276047360.

The previous prime is 1010021131289. The next prime is 1010021131331. The reversal of 1010021131300 is 31311200101.

1010021131300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 31250949 + ... + 31283251.

It is an arithmetic number, because the mean of its divisors is an integer number (30722353088).

Almost surely, 2^{1010021131300} is an apocalyptic number.

1010021131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1010021131300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1106004711168).

1010021131300 is an abundant number, since it is smaller than the sum of its proper divisors (1201988291036).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1010021131300 is a wasteful number, since it uses less digits than its factorization.

1010021131300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35197 (or 35190 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1010021131300 its reverse (31311200101), we get a palindrome (1041332331401).

The spelling of 1010021131300 in words is "one trillion, ten billion, twenty-one million, one hundred thirty-one thousand, three hundred".