Base | Representation |
---|---|
bin | 101111000010000110… |
… | …0100001001110010011 |
3 | 100122201000022102101012 |
4 | 1132010030201032103 |
5 | 3123323020402011 |
6 | 114222202001135 |
7 | 10203632605241 |
oct | 1360414411623 |
9 | 318630272335 |
10 | 101002122131 |
11 | 39920079309 |
12 | 176a94a61ab |
13 | 96a8310811 |
14 | 4c621a1791 |
15 | 29621d9a8b |
hex | 1784321393 |
101002122131 has 2 divisors, whose sum is σ = 101002122132. Its totient is φ = 101002122130.
The previous prime is 101002122043. The next prime is 101002122139. The reversal of 101002122131 is 131221200101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101002122131 - 210 = 101002121107 is a prime.
It is a super-2 number, since 2×1010021221312 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (101002122139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50501061065 + 50501061066.
It is an arithmetic number, because the mean of its divisors is an integer number (50501061066).
Almost surely, 2101002122131 is an apocalyptic number.
101002122131 is a deficient number, since it is larger than the sum of its proper divisors (1).
101002122131 is an equidigital number, since it uses as much as digits as its factorization.
101002122131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 101002122131 its reverse (131221200101), we get a palindrome (232223322232).
The spelling of 101002122131 in words is "one hundred one billion, two million, one hundred twenty-two thousand, one hundred thirty-one".
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