Base | Representation |
---|---|
bin | 101111000010000110… |
… | …0100011111010011011 |
3 | 100122201000022222111012 |
4 | 1132010030203322123 |
5 | 3123323021230042 |
6 | 114222202124135 |
7 | 10203632652326 |
oct | 1360414437233 |
9 | 318630288435 |
10 | 101002133147 |
11 | 39920086613 |
12 | 176a94b064b |
13 | 96a8315836 |
14 | 4c621a57bd |
15 | 29621dce82 |
hex | 1784323e9b |
101002133147 has 2 divisors, whose sum is σ = 101002133148. Its totient is φ = 101002133146.
The previous prime is 101002133077. The next prime is 101002133153. The reversal of 101002133147 is 741331200101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101002133147 - 216 = 101002067611 is a prime.
It is a super-2 number, since 2×1010021331472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101002130147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50501066573 + 50501066574.
It is an arithmetic number, because the mean of its divisors is an integer number (50501066574).
Almost surely, 2101002133147 is an apocalyptic number.
101002133147 is a deficient number, since it is larger than the sum of its proper divisors (1).
101002133147 is an equidigital number, since it uses as much as digits as its factorization.
101002133147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 101002133147 its reverse (741331200101), we get a palindrome (842333333248).
The spelling of 101002133147 in words is "one hundred one billion, two million, one hundred thirty-three thousand, one hundred forty-seven".
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