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101002201310 = 2510100220131
BaseRepresentation
bin101111000010000110…
…0110100100011011110
3100122201000110102222202
41132010030310203132
53123323030420220
6114222203411502
710203633355133
oct1360414644336
9318630412882
10101002201310
113992012284a
12176a9523b92
1396a833a87a
144c621c258a
152962203275
hex17843348de

101002201310 has 8 divisors (see below), whose sum is σ = 181803962376. Its totient is φ = 40400880520.

The previous prime is 101002201309. The next prime is 101002201331. The reversal of 101002201310 is 13102200101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1010022013102 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101002201291 and 101002201300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5050110056 + ... + 5050110075.

It is an arithmetic number, because the mean of its divisors is an integer number (22725495297).

Almost surely, 2101002201310 is an apocalyptic number.

101002201310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

101002201310 is a deficient number, since it is larger than the sum of its proper divisors (80801761066).

101002201310 is a wasteful number, since it uses less digits than its factorization.

101002201310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10100220138.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 101002201310 its reverse (13102200101), we get a palindrome (114104401411).

The spelling of 101002201310 in words is "one hundred one billion, two million, two hundred one thousand, three hundred ten".

Divisors: 1 2 5 10 10100220131 20200440262 50501100655 101002201310