Base | Representation |
---|---|
bin | 10010110100000011… |
… | …01000010100010010 |
3 | 222001220111222101020 |
4 | 21122001220110102 |
5 | 131141134430224 |
6 | 4350124420310 |
7 | 505203141522 |
oct | 113201502422 |
9 | 28056458336 |
10 | 10100311314 |
11 | 43133a9425 |
12 | 1b5a6a7696 |
13 | c4c70c892 |
14 | 6bb5d5682 |
15 | 3e1ac4c79 |
hex | 25a068512 |
10100311314 has 64 divisors (see below), whose sum is σ = 21299589120. Its totient is φ = 3188808000.
The previous prime is 10100311279. The next prime is 10100311343. The reversal of 10100311314 is 41311300101.
It is a junction number, because it is equal to n+sod(n) for n = 10100311293 and 10100311302.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2391897 + ... + 2396115.
It is an arithmetic number, because the mean of its divisors is an integer number (332806080).
Almost surely, 210100311314 is an apocalyptic number.
10100311314 is an abundant number, since it is smaller than the sum of its proper divisors (11199277806).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10100311314 is a wasteful number, since it uses less digits than its factorization.
10100311314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4527.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 10100311314 its reverse (41311300101), we get a palindrome (51411611415).
The spelling of 10100311314 in words is "ten billion, one hundred million, three hundred eleven thousand, three hundred fourteen".
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