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101004002124433 is a prime number
BaseRepresentation
bin10110111101110011010011…
…101010101110001010010001
3111020121212222120102221101121
4112331303103222232022101
5101214322144020440213
6554452333100402241
730163204221323452
oct2675632352561221
9436555876387347
10101004002124433
112a201614037421
12b3b3303b46381
1344488375c8145
141ad28969a3129
15ba252c57a88d
hex5bdcd3aae291

101004002124433 has 2 divisors, whose sum is σ = 101004002124434. Its totient is φ = 101004002124432.

The previous prime is 101004002124401. The next prime is 101004002124457. The reversal of 101004002124433 is 334421200400101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73369708934544 + 27634293189889 = 8565612^2 + 5256833^2 .

It is a cyclic number.

It is not a de Polignac number, because 101004002124433 - 25 = 101004002124401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101004002124398 and 101004002124407.

It is not a weakly prime, because it can be changed into another prime (101004002124733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50502001062216 + 50502001062217.

It is an arithmetic number, because the mean of its divisors is an integer number (50502001062217).

Almost surely, 2101004002124433 is an apocalyptic number.

It is an amenable number.

101004002124433 is a deficient number, since it is larger than the sum of its proper divisors (1).

101004002124433 is an equidigital number, since it uses as much as digits as its factorization.

101004002124433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 101004002124433 its reverse (334421200400101), we get a palindrome (435425202524534).

The spelling of 101004002124433 in words is "one hundred one trillion, four billion, two million, one hundred twenty-four thousand, four hundred thirty-three".