Base | Representation |
---|---|
bin | 11101011001010111110… |
… | …11100001001101111011 |
3 | 10120120010102102200111211 |
4 | 32230223323201031323 |
5 | 113022042402244103 |
6 | 2052002413503551 |
7 | 132655042132036 |
oct | 16545373411573 |
9 | 3516112380454 |
10 | 1010054337403 |
11 | 35a3a8383451 |
12 | 1439091a1bb7 |
13 | 7432b2cc707 |
14 | 36c5b8b201d |
15 | 1b4192a936d |
hex | eb2bee137b |
1010054337403 has 2 divisors, whose sum is σ = 1010054337404. Its totient is φ = 1010054337402.
The previous prime is 1010054337401. The next prime is 1010054337431. The reversal of 1010054337403 is 3047334500101.
It is a weak prime.
It is an emirp because it is prime and its reverse (3047334500101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1010054337403 - 21 = 1010054337401 is a prime.
It is a super-2 number, since 2×10100543374032 (a number of 25 digits) contains 22 as substring.
Together with 1010054337401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1010054337401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505027168701 + 505027168702.
It is an arithmetic number, because the mean of its divisors is an integer number (505027168702).
Almost surely, 21010054337403 is an apocalyptic number.
1010054337403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010054337403 is an equidigital number, since it uses as much as digits as its factorization.
1010054337403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 1010054337403 its reverse (3047334500101), we get a palindrome (4057388837504).
The spelling of 1010054337403 in words is "one trillion, ten billion, fifty-four million, three hundred thirty-seven thousand, four hundred three".
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