Base | Representation |
---|---|
bin | 10110111101111001110101… |
… | …011011110101110101100111 |
3 | 111020122120002001001210100112 |
4 | 112331321311123311311213 |
5 | 101214431022320200012 |
6 | 554455452355203235 |
7 | 30163543006534541 |
oct | 2675716533656547 |
9 | 436576061053315 |
10 | 101011011100007 |
11 | 2a204590461518 |
12 | b3b473b2a651b |
13 | 44493b3724578 |
14 | 1ad2d5d7b8691 |
15 | ba27dca69122 |
hex | 5bde756f5d67 |
101011011100007 has 2 divisors, whose sum is σ = 101011011100008. Its totient is φ = 101011011100006.
The previous prime is 101011011099991. The next prime is 101011011100031. The reversal of 101011011100007 is 700001110110101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101011011100007 - 24 = 101011011099991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101011011099964 and 101011011100000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101011011100507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505505550003 + 50505505550004.
It is an arithmetic number, because the mean of its divisors is an integer number (50505505550004).
Almost surely, 2101011011100007 is an apocalyptic number.
101011011100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
101011011100007 is an equidigital number, since it uses as much as digits as its factorization.
101011011100007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7, while the sum is 14.
Adding to 101011011100007 its reverse (700001110110101), we get a palindrome (801012121210108).
The spelling of 101011011100007 in words is "one hundred one trillion, eleven billion, eleven million, one hundred thousand, seven".
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