101011100100007 has 2 divisors, whose sum is σ = 101011100100008. Its totient is φ = 101011100100006.

The previous prime is 101011100099977. The next prime is 101011100100047. The reversal of 101011100100007 is 700001001110101.

It is a weak prime.

It is an emirp because it is prime and its reverse (700001001110101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101011100100007 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101011100100007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101011100100047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505550050003 + 50505550050004.

It is an arithmetic number, because the mean of its divisors is an integer number (50505550050004).

Almost surely, 2^{101011100100007} is an apocalyptic number.

101011100100007 is a deficient number, since it is larger than the sum of its proper divisors (1).

101011100100007 is an equidigital number, since it uses as much as digits as its factorization.

101011100100007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7, while the sum is 13.

Adding to 101011100100007 its reverse (700001001110101), we get a palindrome (801012101210108).

The spelling of 101011100100007 in words is "one hundred one trillion, eleven billion, one hundred million, one hundred thousand, seven".