Base | Representation |
---|---|
bin | 10110111101111001111010… |
… | …101111101110110100001001 |
3 | 111020122120022020201112211201 |
4 | 112331321322233232310021 |
5 | 101214431213122401301 |
6 | 554455505301024201 |
7 | 30163545141062062 |
oct | 2675717257566411 |
9 | 436576266645751 |
10 | 101011100200201 |
11 | 2a204626788844 |
12 | b3b47650b5061 |
13 | 44493c901ca89 |
14 | 1ad2d6b56d569 |
15 | ba27e57b9201 |
hex | 5bde7abeed09 |
101011100200201 has 2 divisors, whose sum is σ = 101011100200202. Its totient is φ = 101011100200200.
The previous prime is 101011100200189. The next prime is 101011100200207. The reversal of 101011100200201 is 102002001110101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 97822464994576 + 3188635205625 = 9890524^2 + 1785675^2 .
It is a cyclic number.
It is not a de Polignac number, because 101011100200201 - 211 = 101011100198153 is a prime.
It is not a weakly prime, because it can be changed into another prime (101011100200207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505550100100 + 50505550100101.
It is an arithmetic number, because the mean of its divisors is an integer number (50505550100101).
Almost surely, 2101011100200201 is an apocalyptic number.
It is an amenable number.
101011100200201 is a deficient number, since it is larger than the sum of its proper divisors (1).
101011100200201 is an equidigital number, since it uses as much as digits as its factorization.
101011100200201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 10.
Adding to 101011100200201 its reverse (102002001110101), we get a palindrome (203013101310302).
The spelling of 101011100200201 in words is "one hundred one trillion, eleven billion, one hundred million, two hundred thousand, two hundred one".
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