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10101110099497 is a prime number
BaseRepresentation
bin1001001011111101100100…
…0101000100111000101001
31022202122201201201111022021
42102333121011010320221
52310444033141140442
633252215205224441
72061531632121424
oct222773105047051
938678651644267
1010101110099497
11324494735231a
1211717b5402121
135836b8943871
1426cc7979a9bb
15127b4685ae67
hex92fd9144e29

10101110099497 has 2 divisors, whose sum is σ = 10101110099498. Its totient is φ = 10101110099496.

The previous prime is 10101110099467. The next prime is 10101110099581. The reversal of 10101110099497 is 79499001110101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7703533474576 + 2397576624921 = 2775524^2 + 1548411^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10101110099497 is a prime.

It is not a weakly prime, because it can be changed into another prime (10101110099467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050555049748 + 5050555049749.

It is an arithmetic number, because the mean of its divisors is an integer number (5050555049749).

Almost surely, 210101110099497 is an apocalyptic number.

It is an amenable number.

10101110099497 is a deficient number, since it is larger than the sum of its proper divisors (1).

10101110099497 is an equidigital number, since it uses as much as digits as its factorization.

10101110099497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20412, while the sum is 43.

The spelling of 10101110099497 in words is "ten trillion, one hundred one billion, one hundred ten million, ninety-nine thousand, four hundred ninety-seven".