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101011221219973 is a prime number
BaseRepresentation
bin10110111101111010000001…
…111101011000101010000101
3111020122120121200102222202111
4112331322001331120222011
5101214431440113014343
6554455525302541021
730163551140531311
oct2675720175305205
9436576550388674
10101011221219973
112a204689026789
12b3b4799737771
134449418112bcc
141ad2d7d672b41
15ba2801221c9d
hex5bde81f58a85

101011221219973 has 2 divisors, whose sum is σ = 101011221219974. Its totient is φ = 101011221219972.

The previous prime is 101011221219929. The next prime is 101011221220027. The reversal of 101011221219973 is 379912122110101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 59574424091809 + 41436797128164 = 7718447^2 + 6437142^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101011221219973 is a prime.

It is a super-3 number, since 3×1010112212199733 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101011221219473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505610609986 + 50505610609987.

It is an arithmetic number, because the mean of its divisors is an integer number (50505610609987).

Almost surely, 2101011221219973 is an apocalyptic number.

It is an amenable number.

101011221219973 is a deficient number, since it is larger than the sum of its proper divisors (1).

101011221219973 is an equidigital number, since it uses as much as digits as its factorization.

101011221219973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 40.

The spelling of 101011221219973 in words is "one hundred one trillion, eleven billion, two hundred twenty-one million, two hundred nineteen thousand, nine hundred seventy-three".