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101019131 is a prime number
BaseRepresentation
bin1100000010101…
…10110111111011
321001002022012022
412001112313323
5201330103011
614005105055
72334435263
oct601266773
9231068168
10101019131
1152028194
12299b818b
1317c0c645
14d5b87a3
158d068db
hex6056dfb

101019131 has 2 divisors, whose sum is σ = 101019132. Its totient is φ = 101019130.

The previous prime is 101019101. The next prime is 101019133. The reversal of 101019131 is 131910101.

It is a strong prime.

It is an emirp because it is prime and its reverse (131910101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101019131 - 214 = 101002747 is a prime.

It is a super-2 number, since 2×1010191312 = 20409729655990322, which contains 22 as substring.

Together with 101019133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (101019133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50509565 + 50509566.

It is an arithmetic number, because the mean of its divisors is an integer number (50509566).

Almost surely, 2101019131 is an apocalyptic number.

101019131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101019131 is an equidigital number, since it uses as much as digits as its factorization.

101019131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 17.

The square root of 101019131 is about 10050.8273788778. The cubic root of 101019131 is about 465.7303526366.

Adding to 101019131 its reverse (131910101), we get a palindrome (232929232).

The spelling of 101019131 in words is "one hundred one million, nineteen thousand, one hundred thirty-one".