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10103025553005 = 35711178934716661
BaseRepresentation
bin1001001100000100101100…
…1111111100111001101101
31022202211200012222121112210
42103001023033330321231
52311011444020144010
633253133232121033
72061630251163120
oct223011317747155
938684605877483
1010103025553005
11324573a5a2950
12117204a996179
135839327282c8
1426cdbbd283b7
15127c09abcb20
hex9304b3fce6d

10103025553005 has 256 divisors, whose sum is σ = 21642322452480. Its totient is φ = 3895785062400.

The previous prime is 10103025552967. The next prime is 10103025553081. The reversal of 10103025553005 is 50035552030101.

It is not a de Polignac number, because 10103025553005 - 28 = 10103025552749 is a prime.

It is a super-2 number, since 2×101030255530052 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 606379375 + ... + 606396035.

It is an arithmetic number, because the mean of its divisors is an integer number (84540322080).

Almost surely, 210103025553005 is an apocalyptic number.

10103025553005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

10103025553005 is an abundant number, since it is smaller than the sum of its proper divisors (11539296899475).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10103025553005 is a wasteful number, since it uses less digits than its factorization.

10103025553005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17140.

The product of its (nonzero) digits is 11250, while the sum is 30.

Adding to 10103025553005 its reverse (50035552030101), we get a palindrome (60138577583106).

The spelling of 10103025553005 in words is "ten trillion, one hundred three billion, twenty-five million, five hundred fifty-three thousand, five".