10104114131 has 2 divisors, whose sum is σ = 10104114132. Its totient is φ = 10104114130.

The previous prime is 10104114121. The next prime is 10104114133. The reversal of 10104114131 is 13141140101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10104114131 is a prime.

It is a super-2 number, since 2×10104114131² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 10104114133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10104114133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5052057065 + 5052057066.

It is an arithmetic number, because the mean of its divisors is an integer number (5052057066).

Almost surely, 2^10104114131 is an apocalyptic number.

10104114131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10104114131 is an equidigital number, since it uses as much as digits as its factorization.

10104114131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 10104114131 its reverse (13141140101), we get a palindrome (23245254232).

The spelling of 10104114131 in words is "ten billion, one hundred four million, one hundred fourteen thousand, one hundred thirty-one".