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101041514117 is a prime number
BaseRepresentation
bin101111000011010001…
…0110010011010000101
3100122210202102202000122
41132012202302122011
53123413111422432
6114230130151325
710204621461545
oct1360642623205
9318722382018
10101041514117
1139940334075
12176ba722545
1396b352369b
144c674d7325
1529658bb612
hex17868b2685

101041514117 has 2 divisors, whose sum is σ = 101041514118. Its totient is φ = 101041514116.

The previous prime is 101041514081. The next prime is 101041514179. The reversal of 101041514117 is 711415140101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96717268036 + 4324246081 = 310994^2 + 65759^2 .

It is a cyclic number.

It is not a de Polignac number, because 101041514117 - 28 = 101041513861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101041514617) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50520757058 + 50520757059.

It is an arithmetic number, because the mean of its divisors is an integer number (50520757059).

Almost surely, 2101041514117 is an apocalyptic number.

It is an amenable number.

101041514117 is a deficient number, since it is larger than the sum of its proper divisors (1).

101041514117 is an equidigital number, since it uses as much as digits as its factorization.

101041514117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 560, while the sum is 26.

Adding to 101041514117 its reverse (711415140101), we get a palindrome (812456654218).

The spelling of 101041514117 in words is "one hundred one billion, forty-one million, five hundred fourteen thousand, one hundred seventeen".