1010441213017 has 2 divisors, whose sum is σ = 1010441213018. Its totient is φ = 1010441213016.

The previous prime is 1010441212997. The next prime is 1010441213029. The reversal of 1010441213017 is 7103121440101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 806770425616 + 203670787401 = 898204^2 + 451299^2 .

It is an emirp because it is prime and its reverse (7103121440101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1010441213017 - 2³⁵ = 976081474649 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1010441212982 and 1010441213000.

It is not a weakly prime, because it can be changed into another prime (1010441213317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505220606508 + 505220606509.

It is an arithmetic number, because the mean of its divisors is an integer number (505220606509).

Almost surely, 2^{1010441213017} is an apocalyptic number.

It is an amenable number.

1010441213017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010441213017 is an equidigital number, since it uses as much as digits as its factorization.

1010441213017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 672, while the sum is 25.

Adding to 1010441213017 its reverse (7103121440101), we get a palindrome (8113562653118).

The spelling of 1010441213017 in words is "one trillion, ten billion, four hundred forty-one million, two hundred thirteen thousand, seventeen".