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101050650313 is a prime number
BaseRepresentation
bin101111000011100010…
…1101000111011001001
3100122211101121220112021
41132013011220323021
53123422431302223
6114231054044441
710205062232644
oct1360705507311
9318741556467
10101050650313
1139945504248
12177017a9721
1396b53a2012
144c687d4a5b
1529665c365d
hex1787168ec9

101050650313 has 2 divisors, whose sum is σ = 101050650314. Its totient is φ = 101050650312.

The previous prime is 101050650293. The next prime is 101050650329. The reversal of 101050650313 is 313056050101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90136251529 + 10914398784 = 300227^2 + 104472^2 .

It is a cyclic number.

It is not a de Polignac number, because 101050650313 - 221 = 101048553161 is a prime.

It is a super-2 number, since 2×1010506503132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101050650373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50525325156 + 50525325157.

It is an arithmetic number, because the mean of its divisors is an integer number (50525325157).

Almost surely, 2101050650313 is an apocalyptic number.

It is an amenable number.

101050650313 is a deficient number, since it is larger than the sum of its proper divisors (1).

101050650313 is an equidigital number, since it uses as much as digits as its factorization.

101050650313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1350, while the sum is 25.

The spelling of 101050650313 in words is "one hundred one billion, fifty million, six hundred fifty thousand, three hundred thirteen".