1011000100013 has 2 divisors, whose sum is σ = 1011000100014. Its totient is φ = 1011000100012.

The previous prime is 1011000099997. The next prime is 1011000100027. The reversal of 1011000100013 is 3100010001101.

1011000100013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 730679620804 + 280320479209 = 854798^2 + 529453^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011000100013 - 2⁴ = 1011000099997 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011000100213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505500050006 + 505500050007.

It is an arithmetic number, because the mean of its divisors is an integer number (505500050007).

Almost surely, 2^{1011000100013} is an apocalyptic number.

It is an amenable number.

1011000100013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011000100013 is an equidigital number, since it uses as much as digits as its factorization.

1011000100013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 1011000100013 its reverse (3100010001101), we get a palindrome (4111010101114).

The spelling of 1011000100013 in words is "one trillion, eleven billion, one hundred thousand, thirteen".